document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=743400>Question 743400</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The sum of all terms of the arithmetic progression having      ten terms except for the first term is 99 and except for   the sixth term 89. Find the third term of the progression      if the sum of the first term and the fifth term is equal to 10. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #452872 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=452872\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The sum of all terms of the arithmetic progression having  ten terms except for the first term is 99 and except for   the sixth term 89. Find the third term of the progression      if the sum of the first term and the fifth term is equal to 10.\r<BR>\n" );
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document.write( "Sn = n/2[2a+(n-1)d]\r<BR>\n" );
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document.write( "S10 = 5[2a+(9)d]\r<BR>\n" );
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document.write( "S1= 1/2{2a]=>a\r<BR>\n" );
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document.write( "5[2a+9d]-a=99\r<BR>\n" );
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document.write( "5[2a+9d]-a=99\r<BR>\n" );
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document.write( "9a+45d=99<BR>\n" );
document.write( "/9<BR>\n" );
document.write( "a+5d=11....................(1)\r<BR>\n" );
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document.write( "t6=a+5d..........................(2)\r<BR>\n" );
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document.write( "5[2a+9d]-11=89\r<BR>\n" );
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document.write( "10a+45d=100...............................(3)\r<BR>\n" );
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document.write( "solve (1) & (3)\r<BR>\n" );
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document.write( "a=1, d=2\r<BR>\n" );
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document.write( "t3=1+4<BR>\n" );
document.write( "t3=5\r<BR>\n" );
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document.write( " </SPAN>\n" );
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