document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=743376>Question 743376</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I am trying to solve the linear system of equations by graphing. the problem reads x/3+y/5=7/15 and the second part states x/4+3/8y=1/8. I know I must find a common denominator and put the problems into y=mx+b form. I am just having a hard time understanding them. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #452851 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=452851\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> x/3+y/5=7/15\r<BR>\n" );
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document.write( "multiply by 15<BR>\n" );
document.write( "5x+3y= 7\r<BR>\n" );
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document.write( "3y=-5x+7<BR>\n" );
document.write( "y=(-5/3)x+7/3.............................(2)<BR>\n" );
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document.write( "x/4+3/8y=1/8\r<BR>\n" );
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document.write( "multiply by 8\r<BR>\n" );
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document.write( "2x+3y=1<BR>\n" );
document.write( "3y=-2x+1\r<BR>\n" );
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document.write( "y=(-2/3)x+1/3...........................(2)\r<BR>\n" );
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document.write( "Find the x & y intercept points by plugging x=0,y=0 in both equations.								<BR>\n" );
document.write( "equation I								<BR>\n" );
document.write( "when x=	0	y=	2.33	,(	0	,	2.33	)<BR>\n" );
document.write( "when y =	0	x=	7	,(	1.4	,	0	)<BR>\n" );
document.write( "Equation 2								<BR>\n" );
document.write( "when x=	0	y=	0.33	(	0	,	0.33	)<BR>\n" );
document.write( "when y =	0	x=	0.5	(	0	,	0.5	)\r<BR>\n" );
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document.write( "you may take simpler values to graph easily.		\r<BR>\n" );
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document.write( "(2,-1) </SPAN>\n" );
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