document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=743228>Question 743228</A>: <I><SPAN STYLE=\"word-break: break-all;\"> How do I factor b to the third power plus 49b completely. I have broke down into prime factors giving me b*b*b+7*7*b. This gives me b squared plus 49. Please advise if I am doing this polynomial correctly. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #452808 by </B><A HREF=/tutors/aboutme.mpl?userid=Alan3354><B>Alan3354(69443)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Alan3354><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Alan3354><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=452808\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> How do I factor b to the third power plus 49b completely. I have broke down into prime factors giving me b*b*b+7*7*b. This gives me b squared plus 49. Please advise if I am doing this polynomial correctly.<BR>\n" );
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document.write( "You're doing it correctly.<BR>\n" );
document.write( "The only common factor is b<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=b%5E3+%2B+49b+=+b%2A%28b%5E2+%2B+49%29 ALIGN=MIDDLE  ALT=\"b%5E3+%2B+49b+=+b%2A%28b%5E2+%2B+49%29\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "All you can do.<BR>\n" );
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