document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=743226>Question 743226</A>: <I><SPAN STYLE=\"word-break: break-all;\"> An herbalist has 40 oz of herbs costing $3 per ounce. How many ounces of herbs costing $2 per ounce should be mixed with these 40 oz of herbs to produce a mixture costing $2.50 per ounce? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #452807 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=452807\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> An herbalist has 40 oz of herbs costing $3 per ounce. How many ounces of herbs costing $2 per ounce should be mixed with these 40 oz of herbs to produce a mixture costing $2.50 per ounce?<BR>\n" );
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document.write( "Equation:<BR>\n" );
document.write( "value + value = value<BR>\n" );
document.write( "3*40 + 2x = 2.5*40<BR>\n" );
document.write( "120 + 2x = 100<BR>\n" );
document.write( "2x = 20<BR>\n" );
document.write( "x = 10 oz (# of ounces of $2 herbs needed)<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H. </SPAN>\n" );
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