document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=743154>Question 743154</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I KNOW THE THREE SIDES OF A TRIANGLE WHAT ARE THE ANGLES 87\" 42\" 42\" </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #452774 by </B><A HREF=/tutors/aboutme.mpl?userid=Edwin+McCravy><B>Edwin McCravy(20081)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Edwin+McCravy><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Edwin+McCravy><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=452774\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> There is no solution because the sum of the shorter two sides of any triangle is ALWAYS GREATER THAN the longest side.  In this problem, the sum of what are supposed to be the two shorter sides is 42\"+42\"=84\", which is less than what is supposed to be the longest side 87\".  So those three lengths cannot be the sides of a triangle.  \r<BR>\n" );
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