document.write( "Question 64737: I need help with this...\r
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document.write( "Write the slope-intercept form of an equation of the line that passes through thr given point and is perpendicular to the graph of each equation.\r
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document.write( "(-2,-2), y= -1/3x+9\r
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document.write( "I got really confused in class today and my teacher explained how to do these problems in examples. Is there a formula i can use for it? \n" );
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Algebra.Com's Answer #45273 by checkley71(8403)![]() ![]() ![]() You can put this solution on YOUR website! Y=-1/X+9 IS A LINE WITH A SLOPE OF (-1/3) & A Y INTERCEPT OF (0,9). \n" ); document.write( "FOR A LINE TO BE PERPENDICULAR IT MUST HAVE A SLOPE THAT IS THE NEGATIVE RECIPRICAL OF THE LINE IT IS PERPENDICULAT TO. THUS THE SLOPE IS 3 FOR THE PERPENDICULAR LINE THROUGH (-2,-2). \n" ); document.write( "NOW SUBSTITUTE THESE POINTS X=-2, Y=-2 AND THE SLOPE IN THE LINE FORMULA \n" ); document.write( "Y=mX+b WE GET \n" ); document.write( "-2=3(-2)+b \n" ); document.write( "-2=-6+b \n" ); document.write( "B=-2+6 \n" ); document.write( "b=4 SOLUTION FOR THE Y INTERCEPT (0,4) \n" ); document.write( "THUS THE EQUATION FOR THIS LINE IS \n" ); document.write( "Y=3X+4 \n" ); document.write( " |