document.write( "Question 742968: I have been given a very challenging word problem and cannot figure it out. It's on Finding rates. Jeff bicycles 160 miles at the rate of r mph. The same trip would have taken 2 hours longer if he had decreased his speed by 4 mph. Find r. Can you please help me solve this problem?...thanks \n" ); document.write( "
Algebra.Com's Answer #452706 by mananth(16946)\"\" \"About 
You can put this solution on YOUR website!
d=160
\n" ); document.write( "speed = r\r
\n" ); document.write( "\n" ); document.write( "t=160/r\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "d=160
\n" ); document.write( "new speed = r-4\r
\n" ); document.write( "\n" ); document.write( "t= 160/(r-4)\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "time new speed time original speed = 2\r
\n" ); document.write( "\n" ); document.write( "\"160%2F%28r-4%29-160%2Fr=2\"\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "multiply by r(r-2)\r
\n" ); document.write( "\n" ); document.write( "160r-9600+160r= 2r(r-4)\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "320r-9600=2r^2-8r\r
\n" ); document.write( "\n" ); document.write( "2r^2-328r+9600=0\r
\n" ); document.write( "\n" ); document.write( "/2
\n" ); document.write( "r^2-164r+4800=0\r
\n" ); document.write( "\n" ); document.write( "r^2-164r+6724=6724-4800\r
\n" ); document.write( "\n" ); document.write( "(r-82)^2=1924\r
\n" ); document.write( "\n" ); document.write( "r-82=43.86\r
\n" ); document.write( "\n" ); document.write( "r=82-43.86\r
\n" ); document.write( "\n" ); document.write( "r=38.14
\n" ); document.write( "
\n" );