document.write( "Question 742861: Can someone help me the area is 176cm squared and the perimeter 60cm \n" ); document.write( "
Algebra.Com's Answer #452650 by stanbon(75887) ![]() You can put this solution on YOUR website! Can someone help me the area is 176cm squared and the perimeter 60cm \n" ); document.write( "---- \n" ); document.write( "Perimeter = 2(L + W) \n" ); document.write( "60 = 2(L+W) \n" ); document.write( "L + W = 30 \n" ); document.write( "----- \n" ); document.write( "Area = L*W \n" ); document.write( "176 = L*W \n" ); document.write( "=================== \n" ); document.write( "L = 30-W \n" ); document.write( "Substitute for \"L\" and solve for \"W\": \n" ); document.write( "176 = (30-W)W \n" ); document.write( "--- \n" ); document.write( "-W^2 + 30W - 176 = 0 \n" ); document.write( "W^2 -30W + 176 = 0 \n" ); document.write( "--- \n" ); document.write( "(W-22)(W - 8) = 0 \n" ); document.write( "----- \n" ); document.write( "If Width = 22 then L = 8 \n" ); document.write( "If Width = 8 then Length = 22 \n" ); document.write( "----------------------- \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( "========== \n" ); document.write( " |