document.write( "Question 64696This question is from textbook
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document.write( ": can you explain to me step by step if I need to change the whole number into an improper fraction to work the problem \n" );
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Algebra.Com's Answer #45263 by checkley71(8403) ![]() You can put this solution on YOUR website! 7 \n" ); document.write( "-4 2/3 CHANGE THE 7 TO 6 3/3 THEN SUBTRACT THE FRACTIONS AND THE WHOLE NUMBERS THUS \n" ); document.write( "6 3/3 \n" ); document.write( "-4 2/3 \n" ); document.write( "------------ \n" ); document.write( "2 1/3 \n" ); document.write( "------------------------------------------------------------------- \n" ); document.write( "7=6 3/3 because 3/3=1 & 6+1=7 \n" ); document.write( "------------------------------------------------ \n" ); document.write( "7 also = 6 7/7 if you were working with fractions with 7 in the denominator \n" ); document.write( "again 6+7/7=6+1=7 \n" ); document.write( "-------------------------------------------------------------------- \n" ); document.write( "7 also = 6 35/35 if you were working with fractions with 35 in the denominator \n" ); document.write( "again 7=6+35/35=6+1=7\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |