document.write( "Question 64696This question is from textbook
\n" ); document.write( ": can you explain to me step by step if I need to change the whole number into an improper fraction to work the problem \n" ); document.write( "
Algebra.Com's Answer #45263 by checkley71(8403)\"\" \"About 
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7
\n" ); document.write( "-4 2/3 CHANGE THE 7 TO 6 3/3 THEN SUBTRACT THE FRACTIONS AND THE WHOLE NUMBERS THUS
\n" ); document.write( "6 3/3
\n" ); document.write( "-4 2/3
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\n" ); document.write( "2 1/3
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\n" ); document.write( "7=6 3/3 because 3/3=1 & 6+1=7
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\n" ); document.write( "7 also = 6 7/7 if you were working with fractions with 7 in the denominator
\n" ); document.write( "again 6+7/7=6+1=7
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\n" ); document.write( "7 also = 6 35/35 if you were working with fractions with 35 in the denominator
\n" ); document.write( "again 7=6+35/35=6+1=7\r
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