document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=64723>Question 64723</A>: <I><SPAN STYLE=\"word-break: break-all;\"> find the foci of the ellipse: 16x^2 + 25y^2 - 96x + 200y + 144 =0 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #45261 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=45261\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> find the foci of the ellipse: 16x^2 + 25y^2 - 96x + 200y + 144 =0<BR>\n" );
document.write( "16(x^2-(96/16)x+?)+25(y^2+(200/25)y+?)=-144<BR>\n" );
document.write( "16(x^2-6x+3^2) + 25(y^+8y+4^2)=-144+16*3^2+25(4^2)<BR>\n" );
document.write( "16(x+(3/16))^2+25(y+4)^2=400<BR>\n" );
document.write( "[(x+(3/16))^2]/[400/16]+[(y+4)^2]/[400/25]=1<BR>\n" );
document.write( "a=[20/4]=5  ; b=[20/5]=4<BR>\n" );
document.write( "For an ellipse a^2=b^2+c^2<BR>\n" );
document.write( "25=16+c^2<BR>\n" );
document.write( "c=3<BR>\n" );
document.write( "Center of this ellipse is at (-3/16,-4)<BR>\n" );
document.write( "Foci are at ((-3/16)+3,-4) and ((-3/16)-3,-4)<BR>\n" );
document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
document.write( " </SPAN>\n" );
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