document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=742631>Question 742631</A>: <I><SPAN STYLE=\"word-break: break-all;\"> a circle with centre(-3,-5)has one end of its diameter at (5,-3) find other end of the diameter. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #452605 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=452605\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> centre(-3,-5)has one end of its diameter at (5,-3) find other end of the diameter\r<BR>\n" );
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document.write( "center of the circle is the mid point of ends of diameter\r<BR>\n" );
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document.write( "apply mid point formula\r<BR>\n" );
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document.write( "let The end point be (x,y)\r<BR>\n" );
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document.write( "(x+5)/2 = -3<BR>\n" );
document.write( "x+5=-6<BR>\n" );
document.write( "x=-11\r<BR>\n" );
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document.write( "(y-3)/2=-5\r<BR>\n" );
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document.write( "y-3=-10<BR>\n" );
document.write( "y=-7\r<BR>\n" );
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document.write( "(-11,-7) </SPAN>\n" );
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