document.write( "Question 742596: An investor invested a total of 1,900 in two mutual funds. One fund earned a 4% profit while the other earned a 2% profit. If the investors total profit was $58, how much was invested in each mutal fund \n" ); document.write( "

Algebra.Com's Answer #452587 by mananth(16946) $\"\"$ $\"About$

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Part I 4.00% per annum ------------- Amount invested =x
\n" ); document.write( "Part II 2.00% per annum ------------ Amount invested = y
\n" ); document.write( " 1900
\n" ); document.write( "Interest----- 58.00
\n" ); document.write( "
\n" ); document.write( "Part I 4.00% per annum ---x
\n" ); document.write( "Part II 2.00% per annum ---y
\n" ); document.write( "Total investment
\n" ); document.write( "x + 1 y= 1900 -------------1
\n" ); document.write( "Interest on both investments
\n" ); document.write( "4.00% x + 2.00% y= 58
\n" ); document.write( "Multiply by 100
\n" ); document.write( "4 x + 2 y= 5800.00 --------2
\n" ); document.write( "Multiply (1) by -4
\n" ); document.write( "we get
\n" ); document.write( "-4 x -4 y= -7600.00
\n" ); document.write( "Add this to (2)
\n" ); document.write( "0 x -2 y= -1800
\n" ); document.write( "divide by -2
\n" ); document.write( " y = 900
\n" ); document.write( "Part I 4.00% $ 1000
\n" ); document.write( "Part II 2.00% $ 900
\n" ); document.write( "
\n" ); document.write( "CHECK
\n" ); document.write( "1000 --------- 4.00% ------- 40.00
\n" ); document.write( "900 ------------- 2.00% ------- 18.00
\n" ); document.write( "Total -------------------- 58.00
\n" ); document.write( "
\n" ); document.write( "m.ananth@hotmail.ca
\n" ); document.write( " \n" ); document.write( "

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