document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=742574>Question 742574</A>: <I><SPAN STYLE=\"word-break: break-all;\"> 1. Write the following as single expression as a single logarithm<BR>\n" );
document.write( "a)4ln(2x)+ln(6/x) = 2ln(2x)\r<BR>\n" );
document.write( "\n" );
document.write( "Can you please help me out ? Thanks so much in advance:)<BR>\n" );
document.write( "Can you please show the steps it would really help me understand:) </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #452571 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=452571\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 4ln(2x)+ln(6/x) = 2ln(2x) <BR>\n" );
document.write( "-----<BR>\n" );
document.write( "2ln(2x) + ln(6/x) = 0<BR>\n" );
document.write( "--------<BR>\n" );
document.write( "ln(2x)^2 + ln(6/x) = 0<BR>\n" );
document.write( "------<BR>\n" );
document.write( "ln[4x^2*(6/x)] = 0<BR>\n" );
document.write( "------<BR>\n" );
document.write( "ln[24x] = 0<BR>\n" );
document.write( "----<BR>\n" );
document.write( "24x = e^0<BR>\n" );
document.write( "---<BR>\n" );
document.write( "x = 1/24<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
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document.write( " </SPAN>\n" );
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