document.write( "Question 742471: A committe of 5 people is to be selected from four males and six females. What is the probability that the committee created will contain at least 3 males? \n" ); document.write( "
Algebra.Com's Answer #452559 by Edwin McCravy(20062)\"\" \"About 
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A committe of 5 people is to be selected from four males and six females. What is the probability that the committee created will contain at least 3 males?
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document.write( "To succeed we must select committees with  \r\n" );
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document.write( "3 males and 2 females or with 4 males and 1 female\r\n" );
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document.write( "The number of ways to select 3 males and 2 females is C(4,3)C(6,2) ways.\r\n" );
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document.write( "The number of ways to select 4 males and 1 females is C(4,4)C(6,1) ways\r\n" );
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document.write( "We add those to find the numerator of the desired probability\r\n" );
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document.write( "The number of ways to select any committee of 5 is \"10 people Choose 5\",\r\n" );
document.write( "which is C(10,5) ways.\r\n" );
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document.write( "That's the denominator of the desired probability.\r\n" );
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document.write( "Desired probability = \"%22%22=%22%22\"\"%284%2A15%2B1%2A6%29%2F252\"\"%22%22=%22%22\"\"%2860%2B6%29%2F252\"\"%22%22=%22%22\"\"66%2F252\" = \"11%2F42\"  \r\n" );
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document.write( "Edwin
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