document.write( "Question 742471: A committe of 5 people is to be selected from four males and six females. What is the probability that the committee created will contain at least 3 males? \n" ); document.write( "
Algebra.Com's Answer #452559 by Edwin McCravy(20062) You can put this solution on YOUR website! A committe of 5 people is to be selected from four males and six females. What is the probability that the committee created will contain at least 3 males? \n" ); document.write( " \r\n" ); document.write( "To succeed we must select committees with \r\n" ); document.write( "\r\n" ); document.write( "3 males and 2 females or with 4 males and 1 female\r\n" ); document.write( "\r\n" ); document.write( "The number of ways to select 3 males and 2 females is C(4,3)C(6,2) ways.\r\n" ); document.write( "\r\n" ); document.write( "The number of ways to select 4 males and 1 females is C(4,4)C(6,1) ways\r\n" ); document.write( "\r\n" ); document.write( "We add those to find the numerator of the desired probability\r\n" ); document.write( "\r\n" ); document.write( "The number of ways to select any committee of 5 is \"10 people Choose 5\",\r\n" ); document.write( "which is C(10,5) ways.\r\n" ); document.write( "\r\n" ); document.write( "That's the denominator of the desired probability.\r\n" ); document.write( "\r\n" ); document.write( "Desired probability =\n" ); document.write( " |