document.write( "Question 64698This question is from textbook An Incremental Development
\n" ); document.write( ": Find the equation of the line that passes through (3,-5) and is perpendicular to the line that passes through (7,-5) and (-2,-4) \n" ); document.write( "
Algebra.Com's Answer #45255 by checkley71(8403)\"\" \"About 
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FIRST WE FIND THE SLOPE OF THE LINE THROUGH THE 2 POINTS THUS
\n" ); document.write( "(Y2-Y1)/(X2-X1)
\n" ); document.write( "(-4+5)/(-2-7)
\n" ); document.write( "1/-9 IS THE SLOPE OF THE LINE THROUGH ((7,-5)(-2,-4)
\n" ); document.write( "NOW TO IDENTIFY A LINE PERPENDICULAR TO THIS LINE IT HAS TO HAVE A SLOPE OF A NEGATIVE RECIPRICAL OF THIS SLOPE. THUS THE SL;OPE OF A LINE PERPENDICULAR TO THIS LINE THROUGH (3,-5) HAS A SLOPE OF 9. NOW WE SUBSTITUTE THESE X&Y POINTS IN THE FORMULA USING THE NEW SLOPE WE GET
\n" ); document.write( "-5=9*3+b
\n" ); document.write( "-5=27+b
\n" ); document.write( "b=-5-27
\n" ); document.write( "b=-32 THUS THUIS EQUATION IS
\n" ); document.write( "Y=9X-32
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