document.write( "Question 742418: Paddling a canoe with current you can go 12 miles in 2 hours,but against the current the return trip takes 6 hours paddling at the same rate.Find the rate of the current and the rate of paddling in water with no current.Of course,assume the current rate remains the same. \n" ); document.write( "
Algebra.Com's Answer #452509 by MathLover1(20850)![]() ![]() You can put this solution on YOUR website! Let the speed of paddling in still waters be \n" ); document.write( "\n" ); document.write( "DOWNSTREAM \n" ); document.write( "------------------------\r \n" ); document.write( "\n" ); document.write( "if \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "UPSTREAM \n" ); document.write( "--------------------\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "eq.1 + eq.2\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "CHECK\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |