document.write( "Question 742418: Paddling a canoe with current you can go 12 miles in 2 hours,but against the current the return trip takes 6 hours paddling at the same rate.Find the rate of the current and the rate of paddling in water with no current.Of course,assume the current rate remains the same. \n" ); document.write( "
Algebra.Com's Answer #452509 by MathLover1(20850)\"\" \"About 
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Let the speed of paddling in still waters be \"x\" mph and speed of current be \"y\" mph\r
\n" ); document.write( "\n" ); document.write( "DOWNSTREAM
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\n" ); document.write( "\n" ); document.write( "if \"Distance=12mil\" and \"time=2h\", then\r
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\n" ); document.write( "\n" ); document.write( "\"Speed+=%28x%2By%29mph+=+Distance+%2F+time+=+12+%2F2+=+6\"\r
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\n" ); document.write( "\n" ); document.write( "\"x%2B+y+=+6+\"...... eq.1\r
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\n" ); document.write( "\n" ); document.write( "UPSTREAM
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\n" ); document.write( "\n" ); document.write( "\"Speed+=+%28x-y%29+mph+=+Distance+%2F+time+=+12%2F6+=+2\"\r
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\n" ); document.write( "\n" ); document.write( "\"x+-y+=+2\"...... eq.2\r
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\n" ); document.write( "\n" ); document.write( "eq.1 + eq.2\r
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\n" ); document.write( "\n" ); document.write( "\"x%2B6%2Bx-6+=6%2B2\"\r
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\n" ); document.write( "\n" ); document.write( "\"2x+=8\"\r
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\n" ); document.write( "\n" ); document.write( "\"x+=+4mph\", then\r
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\n" ); document.write( "\n" ); document.write( "\"4mph%2B+y+=+6mph+\"\r
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\n" ); document.write( "\n" ); document.write( "\"y+=+2mph\"........ ANSWER\r
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\n" ); document.write( "\n" ); document.write( "CHECK\r
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\n" ); document.write( "\n" ); document.write( "\"12+%2F+%284%2B2%29+=+2+hours\"\r
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\n" ); document.write( "\n" ); document.write( "\"12+%2F+%28+4-2%29+=+6+hours\"\r
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