document.write( "Question 742472: I was needing a little help on this problem:\r
\n" );
document.write( "\n" );
document.write( "What is the smallest of 3 consecutive positive integers if the product of the smaller two integers is 5 less than 5 times the largest integer?\r
\n" );
document.write( "\n" );
document.write( "Thank you! :) \n" );
document.write( "
Algebra.Com's Answer #452486 by rothauserc(4718)![]() ![]() You can put this solution on YOUR website! We are given\r \n" ); document.write( "\n" ); document.write( "What is the smallest of 3 consecutive positive integers if the product of the smaller two integers is 5 less than 5 times the largest integer? \r \n" ); document.write( "\n" ); document.write( "let 3 consecutive positive integers be i, i+1, i+2\r \n" ); document.write( "\n" ); document.write( "then we have,\r \n" ); document.write( "\n" ); document.write( "i*(i+1) = 5*(i+2)-5 \n" ); document.write( " \n" ); document.write( "now, we multiply and simplify\r \n" ); document.write( "\n" ); document.write( "i^2+i = 5i+10-5\r \n" ); document.write( "\n" ); document.write( "regroup and set equal to 0\r \n" ); document.write( "\n" ); document.write( "i^2-4i-5=0\r \n" ); document.write( "\n" ); document.write( "factor this expression into\r \n" ); document.write( "\n" ); document.write( "(i-5)*(i+1) = 0\r \n" ); document.write( "\n" ); document.write( "therefore i=5 or -1, we choose i=5 since our integers are to be positive\r \n" ); document.write( "\n" ); document.write( "and our solution is the integers 5, 6, 7\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |