document.write( "Question 742346: An airplane flying against the wind went 1500 miles in 5 hours and returned with the wind in 3 hours.Assume the wind rate didnt change,find the rate of the airplane and the wind. \n" ); document.write( "
Algebra.Com's Answer #452422 by mananth(16946)\"\" \"About 
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Plane speed =x mph
\n" ); document.write( "wind speed =y mph
\n" ); document.write( "against wind 5 hours
\n" ); document.write( "with wind 3 hours
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\n" ); document.write( "Distance against 1500 miles distance with 1500 miles
\n" ); document.write( "t=d/r against wind -
\n" ); document.write( "1500 / ( x - y )= 5
\n" ); document.write( "5 ( x - y ) = 1500
\n" ); document.write( "5 x - 5 y = 1500 ....................1
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\n" ); document.write( "1500 / ( x + y )= 3
\n" ); document.write( "3 ( x + y ) = 1500
\n" ); document.write( "3 x + 3 y = 1500 ...............2
\n" ); document.write( "Multiply (1) by 1
\n" ); document.write( "Multiply (2) by 1
\n" ); document.write( "we get
\n" ); document.write( "5 x + -5 y = 1500
\n" ); document.write( "3 x + 3 y = 1500
\n" ); document.write( "8 x = 3000
\n" ); document.write( "/ 8
\n" ); document.write( "x = 375.00 mph
\n" ); document.write( "
\n" ); document.write( "plug value of x in (1) y
\n" ); document.write( "5 x -5 y = 1500
\n" ); document.write( "1875 -5 -1875 = 1500
\n" ); document.write( "-5 y = 1500
\n" ); document.write( "-5 y = -375 mph
\n" ); document.write( " y = 75.00
\n" ); document.write( "Plane speed 375.00 mph
\n" ); document.write( "wind speed 75.00 mph
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\n" ); document.write( "m.ananth@hotmail.ca
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