document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=742320>Question 742320</A>: <I><SPAN STYLE=\"word-break: break-all;\"> There are three consecutive integers. If the square of the last plus the product of the other two is 137, find the sum of the integers. If the numbers were three rational number, how would this affect the result? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #452409 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16949)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=452409\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> let the integers be (a-1),a, a+1\r<BR>\n" );
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document.write( "a(a-1)+(a+1)^2=137\r<BR>\n" );
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document.write( "a^2-a+a^2+2a+1=137\r<BR>\n" );
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document.write( "2a^2+a-136=0\r<BR>\n" );
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document.write( "2a^2+17a-16a-136=0\r<BR>\n" );
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document.write( "2a(a+8.5)-16(a+8.5)=0\r<BR>\n" );
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document.write( "(2a-16)(a+8.5)=0\r<BR>\n" );
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document.write( "2a=16 a=8\r<BR>\n" );
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document.write( "7,8,9 \r<BR>\n" );
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document.write( "24 is the sum\r<BR>\n" );
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document.write( "OR a=-8.5\r<BR>\n" );
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document.write( "not an integer so ignore </SPAN>\n" );
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