document.write( "Question 742189: Solve and check
\n" ); document.write( "a) 2log(x-1) = 2+ log 100
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Algebra.Com's Answer #452403 by josgarithmetic(39618)\"\" \"About 
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2*log(x-1)=2+log(100)
\n" ); document.write( "2log(x-1)-log(100)=2
\n" ); document.write( "log(x-1)^2-log(100)=2
\n" ); document.write( "log((1/100)(x-1)^2)=2\r
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\n" ); document.write( "\n" ); document.write( "What you do next depends on what the base is. Assuming you are using some base, b, you would transform:\r
\n" ); document.write( "\n" ); document.write( "\"b%5E2=%281%2F100%29%2A%28x-1%29%5E2\"
\n" ); document.write( "Also, looking carefully at the factor on the right side,
\n" ); document.write( "\"b%5E2=%28%28x-1%29%2F10%29%5E2\"
\n" ); document.write( "Seeing that, the base must be equal to the expression shown in the same position on the rightside:
\n" ); document.write( "\"b=%28x-1%29%2F10\".\r
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\n" ); document.write( "\n" ); document.write( "From this, \"10b=x-1\"
\n" ); document.write( "\"highlight%28x=10b%2B1%29\" You need to know the value of b in order to find anything further.
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