document.write( "Question 742294: this is solving two equations using substitution.
\n" ); document.write( "4x+3y=15 and 5x-2y=13. I have tried: 4x+3y=15 subtracted 4 from both sides and then divided it by 3 to get the y by its self and then I plugged it into the second equation but I cant find the correct answer after this.
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Algebra.Com's Answer #452401 by josgarithmetic(39618)\"\" \"About 
You can put this solution on YOUR website!
4x+3y=15 and 5x-2y=13.\r
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\n" ); document.write( "\n" ); document.write( "\" tried: 4x+3y=15 subtracted 4 from both sides and then divided it by 3 to get the y by its self and then I plugged it into the second equation but \"\r
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\n" ); document.write( "\n" ); document.write( "First Equation: \"4x%2B3y=15\"
\n" ); document.write( "\"3y=15-4x\"
\n" ); document.write( "\"y=15%2F3-4x%2F3=5-%284%2F3%29x\"\r
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\n" ); document.write( "\n" ); document.write( "Second Equation: \"5x-2%28y%29=13\"
\n" ); document.write( "\"5x-2%285-4x%2F3%29=13\", the substitution
\n" ); document.write( "\"5x-10%2B8x%2F3=13\"
\n" ); document.write( "\"5x%2B8x%2F3-10=13\"
\n" ); document.write( "\"%285%2B8%2F3%29x=13%2B10\"
\n" ); document.write( "\"%2815%2F3%2B8%2F3%29x=23\"
\n" ); document.write( "\"%2823%2F3%29x=23\"
\n" ); document.write( "\"x=23%2A%283%2F23%29\"
\n" ); document.write( "Final Answer for x: \"highlight%28x=3%29\"
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