document.write( "Question 742294: this is solving two equations using substitution.
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document.write( "4x+3y=15 and 5x-2y=13. I have tried: 4x+3y=15 subtracted 4 from both sides and then divided it by 3 to get the y by its self and then I plugged it into the second equation but I cant find the correct answer after this. \n" );
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Algebra.Com's Answer #452401 by josgarithmetic(39618)![]() ![]() ![]() You can put this solution on YOUR website! 4x+3y=15 and 5x-2y=13.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "\" tried: 4x+3y=15 subtracted 4 from both sides and then divided it by 3 to get the y by its self and then I plugged it into the second equation but \"\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "First Equation: \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Second Equation: \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "Final Answer for x: |