document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=742300>Question 742300</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A committee of four is chosen at random from a group of 8 women and 5 men. Find the probability that the committee contains at least one man.  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #452400 by </B><A HREF=/tutors/aboutme.mpl?userid=jim_thompson5910><B>jim_thompson5910(35256)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=jim_thompson5910><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=452400\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> There are 8 C 4 = 70 ways to choose a group with all women.\r<BR>\n" );
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document.write( "Note: I'm using the formula shown <a  rel=nofollow HREF=\"http://en.wikipedia.org/wiki/Combination\">here</a>\r<BR>\n" );
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document.write( "There are 13 C 4 = 715 ways to choose a group of men and women.\r<BR>\n" );
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document.write( "So there are 715 - 70  = 645 ways to choose a group with at least one man.\r<BR>\n" );
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document.write( "This means the probability is 645/715 = 129/143 = 0.9020979 (so roughly a 90.20979% chance) </SPAN>\n" );
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