document.write( "Question 742235: John has a collection of nickels,dimes, and quarters. Altogether, there are 241 coins worth $26.20. There are 4 more nickels than dimes. How many of each type of coin are in the collection. \n" ); document.write( "
Algebra.Com's Answer #452381 by tommyt3rd(5050)\"\" \"About 
You can put this solution on YOUR website!
# of Coins: N-nickels, D-dimes, Q-quarters\r
\n" ); document.write( "\n" ); document.write( "there are 241 coins - means \"N%2BD%2BQ=241\"\r
\n" ); document.write( "\n" ); document.write( "worth $26.20 - means \"0.05N%2B0.10D%2B0.25Q=%2426.20\", but if we multiply 20 we get\r
\n" ); document.write( "\n" ); document.write( "\"N%2B2D%2B5Q=524\"\r
\n" ); document.write( "\n" ); document.write( "There are 4 more nickels than dimes means \"D%2B4=N\"\r
\n" ); document.write( "\n" ); document.write( "So we have 3 equations and 3 unknowns:\r
\n" ); document.write( "\n" ); document.write( "\"N%2B2D%2B5Q=524\"
\n" ); document.write( "\"N%2BD%2BQ=241\"
\n" ); document.write( "\"D%2B4=N\"\r
\n" ); document.write( "\n" ); document.write( "So we begin...\r
\n" ); document.write( "\n" ); document.write( "5 times the second equation minus the first equation will eliminate Q:\r
\n" ); document.write( "\n" ); document.write( "\"5%28N%2BD%2BQ%29-%28N%2B2D%2B5Q%29=5%28241%29-524\"
\n" ); document.write( "\"5N%2B5D%2B5Q-N-2D-5Q=681\"
\n" ); document.write( "\"4N%2B3D=681\"\r
\n" ); document.write( "\n" ); document.write( "Since N=D+4 we can write \"4N%2B3D=681\" as\r
\n" ); document.write( "\n" ); document.write( "\"4%28D%2B4%29%2B3D=681\"\r
\n" ); document.write( "\n" ); document.write( "\"7D%2B16=681\"
\n" ); document.write( "\"7D=665\"
\n" ); document.write( "\"D=95\" (95 dimes)\r
\n" ); document.write( "\n" ); document.write( "This means that there D+4=95+4=99 nickels\r
\n" ); document.write( "\n" ); document.write( "Finally we can see that there must be 241-99-95=47 quarters\r
\n" ); document.write( "\n" ); document.write( "(so there are 99 nickels, 95 dimes and 47 quarters)
\n" ); document.write( "
\n" );