document.write( "Question 741417: |2x-1/3|≥(5)/(6) \n" ); document.write( "
Algebra.Com's Answer #452379 by lwsshak3(11628)\"\" \"About 
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|2x-1/3|≥(5)/(6)
\n" ); document.write( "2x-1/3-(5)/(6)≥0
\n" ); document.write( "LCD:6
\n" ); document.write( "12x-2-5≥0
\n" ); document.write( "12x≥7
\n" ); document.write( "x=≥7/12
\n" ); document.write( "or
\n" ); document.write( "-2x+1/3-(5)/(6)≥0
\n" ); document.write( "LCD:6
\n" ); document.write( "-12x+2-5≥0
\n" ); document.write( "-12x≥3
\n" ); document.write( "x=≤-3/12=-1/4
\n" ); document.write( "..
\n" ); document.write( "number line:
\n" ); document.write( "<===-1/4].......[7/12===>
\n" ); document.write( "solution: (-∞,-1/4] U [7/12,∞)
\n" ); document.write( " ..
\n" ); document.write( "check:
\n" ); document.write( "For x≥7/12
\n" ); document.write( "|2x-1/3|=|14/12-4/12|=10/12≥5/6
\n" ); document.write( "..
\n" ); document.write( "For x≤-1/4
\n" ); document.write( "|2x-1/3|=|-1/2-4/12|=10/12≥5/6\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( " \n" ); document.write( "
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