document.write( "Question 742265: hans opens a savings account by depositing $1200 in an account that earns 3% interest compounded weekly. how much will his investment be worth in 10 years? assume there are exactly 52 weeks in a year and round your answer to the nearest cent
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Algebra.Com's Answer #452375 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
Use the compound interest formula: \r
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\n" ); document.write( "\n" ); document.write( "A = P(1+r/n)^(n*t)\r
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\n" ); document.write( "\n" ); document.write( "where\r
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\n" ); document.write( "\n" ); document.write( "A = amount in the account after t years\r
\n" ); document.write( "\n" ); document.write( "P = initial amount invested\r
\n" ); document.write( "\n" ); document.write( "r = interest rate (in decimal form)\r
\n" ); document.write( "\n" ); document.write( "n = compounding frequency\r
\n" ); document.write( "\n" ); document.write( "t = number of years\r
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\n" ); document.write( "\n" ); document.write( "In this case\r
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\n" ); document.write( "\n" ); document.write( "A = unknown (we're solving for this)\r
\n" ); document.write( "\n" ); document.write( "P = 1200\r
\n" ); document.write( "\n" ); document.write( "r = 0.03 (3% = 3/100 = 0.03)\r
\n" ); document.write( "\n" ); document.write( "n = 52 (we're compounding the amount in the account 52 times a year)\r
\n" ); document.write( "\n" ); document.write( "t = 10\r
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\n" ); document.write( "\n" ); document.write( "Plug all these values into the equation to get...\r
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\n" ); document.write( "\n" ); document.write( "\"A+=+P%281%2Br%2Fn%29%5E%28n%2At%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"A+=+1200%281%2B0.03%2F52%29%5E%2852%2A10%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"A+=+1200%281%2B0.000576923076923077%29%5E%2852%2A10%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"A+=+1200%281.00057692307692%29%5E%2852%2A10%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"A+=+1200%281.00057692307692%29%5E%28520%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"A+=+1200%281.34974204283122%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"A+=+1619.69045139747\"\r
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\n" ); document.write( "\n" ); document.write( "\"A+=+1619.69\" Don't forget to round to the nearest penny.\r
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\n" ); document.write( "\n" ); document.write( "So his investment will be worth $1,619.69 in 10 years.
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