document.write( "Question 742265: hans opens a savings account by depositing $1200 in an account that earns 3% interest compounded weekly. how much will his investment be worth in 10 years? assume there are exactly 52 weeks in a year and round your answer to the nearest cent
\n" );
document.write( " \n" );
document.write( "
Algebra.Com's Answer #452375 by jim_thompson5910(35256)![]() ![]() ![]() You can put this solution on YOUR website! Use the compound interest formula: \r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "A = P(1+r/n)^(n*t)\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "------------------------------------------\r \n" ); document.write( "\n" ); document.write( "where\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "A = amount in the account after t years\r \n" ); document.write( "\n" ); document.write( "P = initial amount invested\r \n" ); document.write( "\n" ); document.write( "r = interest rate (in decimal form)\r \n" ); document.write( "\n" ); document.write( "n = compounding frequency\r \n" ); document.write( "\n" ); document.write( "t = number of years\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "In this case\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "A = unknown (we're solving for this)\r \n" ); document.write( "\n" ); document.write( "P = 1200\r \n" ); document.write( "\n" ); document.write( "r = 0.03 (3% = 3/100 = 0.03)\r \n" ); document.write( "\n" ); document.write( "n = 52 (we're compounding the amount in the account 52 times a year)\r \n" ); document.write( "\n" ); document.write( "t = 10\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "------------------------------------------\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Plug all these values into the equation to get...\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "So his investment will be worth $1,619.69 in 10 years. \n" ); document.write( " \n" ); document.write( " |