document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=742213>Question 742213</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The sum of the infinite geometric series with a first term of -6 and a common ratio of 1/4  is:?\r<BR>\n" );
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document.write( "Thank you!  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #452358 by </B><A HREF=/tutors/aboutme.mpl?userid=tommyt3rd><B>tommyt3rd(5050)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=tommyt3rd><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=tommyt3rd><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=452358\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> a = -6<BR>\n" );
document.write( "r = 1/4\r<BR>\n" );
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document.write( "S = a/(1-r)\r<BR>\n" );
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document.write( "S = -6/(1-1/4)\r<BR>\n" );
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document.write( "S = -6/(3/4)\r<BR>\n" );
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document.write( "S = -6(4/3)\r<BR>\n" );
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document.write( "S = -8 </SPAN>\n" );
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