document.write( "Question 742097: \"sqrt%286x%2B7%29-sqrt%283x%2B3%29=1\" \n" ); document.write( "
Algebra.Com's Answer #452307 by KMST(5328)\"\" \"About 
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\n" ); document.write( "Having 2 square roots in an equation, make it a little more complicated to solve than an equation with just one square root.
\n" ); document.write( "As for the simpler equations with square roots, you would square both sides of an equal sign; find solutions to the new equation, and then check those solutions against the original equation.
\n" ); document.write( "However, the arithmetic is usually easier if you start with one square root on each side of the equal sign, so the recommended first step (before the squaring) is
\n" ); document.write( "\"sqrt%286x%2B7%29-sqrt%283x%2B3%29=1\" --> \"sqrt%286x%2B7%29=sqrt%283x%2B3%29%2B1\"
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\n" ); document.write( "FINDING POSSIBLE SOLUTIONS:
\n" ); document.write( "Then, we square both sides to get
\n" ); document.write( "\"6x%2B7=3x%2B3%2B1%2B2sqrt%283x%2B3%29\" and simplify to \"3x%2B3=2sqrt%283x%2B3%29\"
\n" ); document.write( "At this point we can square again and keep chugging along, to get to the solutions.
\n" ); document.write( "Alternatively, if we define \"y=sqrt%283x%2B3%29\" the equation above can be written as
\n" ); document.write( "\"y%5E2=2y\" --> \"y%5E2-2y=0\" --> \"y%28y-2%29=0\"
\n" ); document.write( "with solutions \"y=0\" and \"y=2\", which mean
\n" ); document.write( "\"sqrt%283x%2B3%29=0\" --> \"3x%2B3=0\" --> \"3x=-3\" --> \"x=-1\" and
\n" ); document.write( "\"sqrt%283x%2B3%29=2\" --> \"3x%2B3=4\" --> \"3x=1\" --> \"x=1%2F3\"
\n" ); document.write( "Any way we get to them, our possible solutions are \"x=-1\" and \"x=1%2F3\".
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\n" ); document.write( "CHECKING:
\n" ); document.write( "\"x=-1\" makes the original equation true:
\n" ); document.write( ",
\n" ); document.write( "so \"highlight%28x=-1%29\" is a solution.
\n" ); document.write( "\"x=1%2F3\" also makes the original equation true:
\n" ); document.write( ",
\n" ); document.write( "so \"highlight%28x=1%2F3%29\" is also a solution.
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