document.write( "Question 742185: Solve and check
\n" );
document.write( "a) log(x+2)+log(x-1)=1
\n" );
document.write( "b) log(3x+2)+log(x-1) = 2
\n" );
document.write( "c) 2log(x-1) = 2+log 100\r
\n" );
document.write( "\n" );
document.write( "Can you please help me out? thanks so much in advance:)
\n" );
document.write( "Can you show the work too because I will understand better thankyou:) \n" );
document.write( "
Algebra.Com's Answer #452301 by mananth(16946)![]() ![]() You can put this solution on YOUR website! log(x+2)+log(x-1)=1\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "log((x+2)(x-1))=1 \n" ); document.write( "(x+2)(x-1)=10^1\r \n" ); document.write( "\n" ); document.write( "x^2+x-2=10\r \n" ); document.write( "\n" ); document.write( "x^2+x-12=0\r \n" ); document.write( "\n" ); document.write( "(x+4)(x-3)=0\r \n" ); document.write( "\n" ); document.write( "x=3 ignore negative\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "b) log(3x+2)+log(x-1) = 2 \n" ); document.write( "c) 2log(x-1) = 2+log 100 \n" ); document.write( " \n" ); document.write( " |