document.write( "Question 742185: Solve and check
\n" ); document.write( "a) log(x+2)+log(x-1)=1
\n" ); document.write( "b) log(3x+2)+log(x-1) = 2
\n" ); document.write( "c) 2log(x-1) = 2+log 100\r
\n" ); document.write( "\n" ); document.write( "Can you please help me out? thanks so much in advance:)
\n" ); document.write( "Can you show the work too because I will understand better thankyou:)
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Algebra.Com's Answer #452301 by mananth(16946)\"\" \"About 
You can put this solution on YOUR website!
log(x+2)+log(x-1)=1\r
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\n" ); document.write( "\n" ); document.write( "log((x+2)(x-1))=1
\n" ); document.write( "(x+2)(x-1)=10^1\r
\n" ); document.write( "\n" ); document.write( "x^2+x-2=10\r
\n" ); document.write( "\n" ); document.write( "x^2+x-12=0\r
\n" ); document.write( "\n" ); document.write( "(x+4)(x-3)=0\r
\n" ); document.write( "\n" ); document.write( "x=3 ignore negative\r
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\n" ); document.write( "\n" ); document.write( "b) log(3x+2)+log(x-1) = 2
\n" ); document.write( "c) 2log(x-1) = 2+log 100
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