document.write( "Question 64675: Janet kim is now 13 years old, her father is now 31\r
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document.write( "write an equation stating that jeong is twice as old as janet, then solve it to find out when jeong is twice as old as janet \n" );
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Algebra.Com's Answer #45230 by ptaylor(2198)![]() ![]() You can put this solution on YOUR website! First off, I'm assuming that Jeong is Janet's father.\r \n" ); document.write( "\n" ); document.write( "Now Janet is 13 and Jeong is 31\r \n" ); document.write( "\n" ); document.write( "Let's say that in x years from now Jeong will be twice as old as Janet\r \n" ); document.write( "\n" ); document.write( "In x years from now, Janet will be 13+x years old \n" ); document.write( "Jeong will be 31+x years old which has to be twice as old as Janet (2(13+x)) \r \n" ); document.write( "\n" ); document.write( "So our equation to solve is:\r \n" ); document.write( "\n" ); document.write( "31+x=2(13+x) simplifying, we get: \n" ); document.write( "31+x=26+2x collecting like terms, we will have: \n" ); document.write( "31-26=2x-x or \n" ); document.write( "x=5 years\r \n" ); document.write( "\n" ); document.write( "ck \n" ); document.write( "2(13+5)=31+5 \n" ); document.write( "2(18)=36 \n" ); document.write( "36=36\r \n" ); document.write( "\n" ); document.write( "Hope this helps. Happy holidays.-----ptaylor \n" ); document.write( " |