document.write( "Question 741964: An economics professor randomly selected 25 millionaires in the United States. The average age of these millionaires was 54.8 years with a sample standard deviation of 7.9 years. What is the 99% confidence interval for the mean age, µ, of all United States millionaires? \n" ); document.write( "
Algebra.Com's Answer #452217 by stanbon(75887)\"\" \"About 
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An economics professor randomly selected 25 millionaires in the United States. The average age of these millionaires was 54.8 years with a sample standard deviation of 7.9 years. What is the 99% confidence interval for the mean age, µ, of all United States millionaires?
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\n" ); document.write( "x-bar = 54.8
\n" ); document.write( "ME = 2.5758*7.9/sqrt(25) = 4.070
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\n" ); document.write( "99% CI: 54.8-4.070 < u < 54.8+4.070
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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