document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=741837>Question 741837</A>: <I><SPAN STYLE=\"word-break: break-all;\"> the length of a rectangular box is 3 inches more than twice the width. the perimeter is 36. find the length and width   </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #452162 by </B><A HREF=/tutors/aboutme.mpl?userid=only4christ><B>only4christ(12)</B></A><img src=\"/images/stars/stars-06.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=only4christ><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=452162\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The formula for perimeter is: P = L + L + W + W  or P = 2L + 2W\r<BR>\n" );
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document.write( "Given: Perimeter=36 and L=2W+3\r<BR>\n" );
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document.write( "All we need to do is substitute this into the formula.\r<BR>\n" );
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document.write( "36=2(2W+3) + 2W<BR>\n" );
document.write( "36=4W+6+2W   remove the parenthesis by distributing the 2<BR>\n" );
document.write( "36=6W+6      collect like terms  (numbers with variables)<BR>\n" );
document.write( "36-6=6W      collect like terms (numbers without variables)<BR>\n" );
document.write( "30=6W        divide both sides by 6<BR>\n" );
document.write( "5 = W\r<BR>\n" );
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document.write( "Since L = 2W + 3, then L = 2(5)+3 = 13 </SPAN>\n" );
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