document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=741823>Question 741823</A>: <I><SPAN STYLE=\"word-break: break-all;\"> What must I show to prove the theorem given below?: \r<BR>\n" );
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document.write( "The median drawn to the base of an isosceles triangle bisects the vertex angle. (Basically, picture an isosceles triangle with sides AB and AC congruent, and X bisects the triangle, cutting it in half, so that BX is congruent to XC.)  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #452160 by </B><A HREF=/tutors/aboutme.mpl?userid=fcabanski><B>fcabanski(1391)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=fcabanski><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=452160\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> AB is congruent AC - Definition of an Isosceles triangle<P><BR>\n" );
document.write( "BX is congruent to XC - Definition of a bisector<P><BR>\n" );
document.write( "AX = AX - Reflexive property of equality  (draw lines over the AX)<P><BR>\n" );
document.write( "AX congruent to AX - definition of congruent.<P><BR>\n" );
document.write( "Triangle ABX congruent to triangle ACX - SSS<P><BR>\n" );
document.write( "Angle BAX congruent angle CAX - CPCTC (corresponding parts of congruent triangles are congruent<P><BR>\n" );
document.write( "AX bisects angle BAC - Definition of angle bisector.<BR>\n" );
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