document.write( "Question 741767: find 3 consecutive even integers such that 4 times the sum of the first and the third is 8 less than six times the second \n" ); document.write( "
Algebra.Com's Answer #452152 by only4christ(12) ![]() You can put this solution on YOUR website! Let x = 1st consecutive even integer \n" ); document.write( "Then, x + 2 = 2nd consecutive even integer \n" ); document.write( "And, x + 4 = 3rd consecutive even integer\r \n" ); document.write( "\n" ); document.write( "Now, we build our equation based on the words given to us.\r \n" ); document.write( "\n" ); document.write( "4(x + x + 4) = 6(x + 2) - 8\r \n" ); document.write( "\n" ); document.write( "The part on the left is 4 times the sum of the first and third integer \n" ); document.write( "The part on the right is 8 less than 6 times the sum of the second integer\r \n" ); document.write( "\n" ); document.write( "Now, we just need to remove parenthesis, collect like terms and solve for x. \n" ); document.write( "This \"x\" will give us the first integer and putting it back into the other expressions given for the 2nd and 3rd integers will give us those.\r \n" ); document.write( "\n" ); document.write( "4(x + x + 4) = 6(x + 2) - 8 \n" ); document.write( "4(2x + 4) = 6(x + 2) - 8 Collect like terms on the left side \n" ); document.write( "8x + 16 = 6x + 12 - 8 Remove parenthesis by distributing \n" ); document.write( "8x + 16 = 6x + 4 Collect like terms on the right side \n" ); document.write( "8x - 6x = 4 - 16 Collect like terms: variables on left side and numbers without variables on the right side\r \n" ); document.write( "\n" ); document.write( "2x = -12 Divide both sides by 2 \n" ); document.write( "x = -6 This is the first integer \n" ); document.write( "x + 2 = -6 + 2 = -4 This is the second integer \n" ); document.write( "x + 4 = -6 + 4 = -2 This is the third integer \n" ); document.write( " |