document.write( "Question 741620: Find the value of that makes the statement true.\r
\n" ); document.write( "\n" ); document.write( "log20x=-1\r
\n" ); document.write( "\n" ); document.write( "
\n" ); document.write( "

Algebra.Com's Answer #452094 by rapaljer(4671)\"\" \"About 
You can put this solution on YOUR website!
\"log+%2820%2Cx%29+=+-1\" translates by the definition of logarithms to \"20%5E-1+=+x\"\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Therefore, \"x=20%5E-1+=+1%2F20\".\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Dr. Robert J. Rapalje, Retired
\n" ); document.write( "Seminole State College of Florida\r
\n" ); document.write( "\n" ); document.write( "
\n" ); document.write( "
\n" );