document.write( "Question 741511: Susan leaves home at 8am, driving to a friend's cabin. Her sister, Carol, leaves home an hour later also driving to the cabin. By driving 7 mph faster than Susan, Carol overtakes Susan at 2pm.\r
\n" ); document.write( "\n" ); document.write( "What was the average speed of each sister?
\n" ); document.write( "How far do they drive before Carol overtakes Susan?\r
\n" ); document.write( "\n" ); document.write( "Please show work, if you have to.\r
\n" ); document.write( "\n" ); document.write( "Thank you \n" ); document.write( "

Algebra.Com's Answer #452029 by solver91311(24713) $\"\"$ $\"About$

You can put this solution on YOUR website!
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\n" ); document.write( "\n" ); document.write( "From 8 am to 2 pm is 6 hours, so Susan drove at

miles per hour for 6 hours and therefore travelled

miles. Carol only drove for 5 hours, because she left one hour later. But she travelled at

miles per hour, so she travelled

miles. Those two distances have to be equal, so set them equal and solve for

. Once you know

, Susan's speed, you can add 7 to get Carol's speed. Calculate

to get the distance traveled. Then calculate

to check your work.\r
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\n" ); document.write( "\n" ); document.write( "John
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\n" ); document.write( "Egw to Beta kai to Sigma
\n" ); document.write( "My calculator said it, I believe it, that settles it
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$\"The$

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