document.write( "Question 741339: A launched rocket has an altitude, in meters, given by the polynomial h+vt-4.9t^2,where h is the height , in meters, from which the launch occurs, at velocity v in meters per second, and t is the number of seconds for which the rocket is airborne. If a rocket is launched from the top of a tower 50 meters high with an initial upward speed of 30 meters per second, what will its height be after 2 seconds?
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document.write( "its height will be ___ meters
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document.write( "(round to the nearest tenth) \n" );
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Algebra.Com's Answer #451971 by richwmiller(17219)![]() ![]() You can put this solution on YOUR website! H=h+vt-4.9t^2 \n" ); document.write( "plug in 50 for small h \n" ); document.write( "2 for t \n" ); document.write( "30 for v \n" ); document.write( "H=h+vt-4.9t^2 \n" ); document.write( "H=50+30*2-4.9*(2^2) \n" ); document.write( "H=50+60-4.9*4 \n" ); document.write( "H=110-19.6 \n" ); document.write( "H=90.4 meters\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |