document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=741267>Question 741267</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Russ and Holly from St. Croix say their weather is very regular. It varies from a low of 62 F at 3:00 am to a high of 78 F at 3:00 pm. Find a formula that gives their temperature in terms of hours after 3:00 am </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #451933 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=451933\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Russ and Holly from St. Croix say their weather is very regular. It varies from a low of 62 F at 3:00 am to a high of 78 F at 3:00 pm. Find a formula that gives their temperature in terms of hours after 3:00 am<BR>\n" );
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document.write( "you have two points: (0,62) and (12,78)<BR>\n" );
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document.write( "slope = (78-62)/(12-0) = 16/12 = 4/3<BR>\n" );
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document.write( "Form: y = mx + b<BR>\n" );
document.write( "Solve for \"b\":<BR>\n" );
document.write( "62 = (4/3)0 + b<BR>\n" );
document.write( "b = 62<BR>\n" );
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document.write( "Equation:<BR>\n" );
document.write( "y = (4/3)x + 62<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H. </SPAN>\n" );
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