document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=741232>Question 741232</A>: <I><SPAN STYLE=\"word-break: break-all;\"> \r<BR>\n" );
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document.write( "Hi , do help me with this few problems sums , thank you :)<BR>\n" );
document.write( "A father is 30 years older than his son. In 6 years' time ,<BR>\n" );
document.write( "he will be twice as old as his son. What are their present ages ? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #451917 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley79><B>checkley79(3341)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley79><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=451917\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> F=S+30<BR>\n" );
document.write( "F+6=2S<BR>\n" );
document.write( "(S+30)+6=2S<BR>\n" );
document.write( "S+36=2S<BR>\n" );
document.write( "S-2S=-36<BR>\n" );
document.write( "-S=-36<BR>\n" );
document.write( "S=36 YEARS OLD FOR THE SON.<BR>\n" );
document.write( "F=36+30<BR>\n" );
document.write( "F=66 YEARS OLD FOR THE FATHER.<BR>\n" );
document.write( "66+6=2*36<BR>\n" );
document.write( "72=72<BR>\n" );
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