document.write( "Question 741194: The C.P. of two watches taken together is Rs. 840. If by selling one at a profit of 16% and the other at a loss of 12%, there is no loss or gain in the whole transaction, then the C.P of the two watches are respectively: (Ans.: Rs. 360, Rs. 480) \n" ); document.write( "

Algebra.Com's Answer #451903 by mananth(16946) $\"\"$ $\"About$

You can put this solution on YOUR website!
x= cost of 1 watch
\n" ); document.write( "y= cost of second watch
\n" ); document.write( "
\n" ); document.write( "1.00 x + 1.00 y = 840.00 .............1
\n" ); document.write( "Total value
\n" ); document.write( "0.16 x -0.12 y = 0.00 .............2
\n" ); document.write( "Eliminate y
\n" ); document.write( "multiply (1)by 0.12
\n" ); document.write( "Multiply (2) by 1.00
\n" ); document.write( "0.12 x 0.12 y = 100.80
\n" ); document.write( "0.16 x -0.12 y = 0.00
\n" ); document.write( "Add the two equations
\n" ); document.write( "0.28 x = 100.80
\n" ); document.write( "/ 0.28
\n" ); document.write( "x = 360.00
\n" ); document.write( "plug value of x in (1)
\n" ); document.write( "1.00 x + 1.00 y = 840.00
\n" ); document.write( "360.00 + y = 840.00
\n" ); document.write( " y = 840.00 -360.00
\n" ); document.write( " y = 480.00
\n" ); document.write( " y = 480.00
\n" ); document.write( "x= 360.00 cost of 1 watch 0.00
\n" ); document.write( "y= 480.00 cost of second watch 0.00
\n" ); document.write( "m.ananth@hotmail.ca
\n" ); document.write( " \n" ); document.write( "

\n" );