document.write( "Question 741213: Respected Sir,
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document.write( "Please help me to solve this question:\r
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document.write( "If(n+2)!=60[(n-1)!],find n.
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document.write( "Thank you in anticipation. \n" );
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Algebra.Com's Answer #451901 by mananth(16946)![]() ![]() You can put this solution on YOUR website! If (n+2)! = 60[(n-1)!], n=? \n" ); document.write( "(n+2)! = 60* ( (n-1)! ) \n" ); document.write( "(n+2)! = (n+2) * (n+1) * (n) * (n-1)! \n" ); document.write( "{ (n+2) * (n+1) * (n) * (n-1)! } = 60* ( (n-1)! ) \n" ); document.write( "=> { (n+2) * (n+1) * (n) * (n-1)! } = 60*( (n-1)! )\r \n" ); document.write( "\n" ); document.write( "=> n3 + 3n2 +2n - 60 = 0 \n" ); document.write( "for n=3 we get 0 Substitute n = 3 \n" ); document.write( "=>( n3 + 3n2 +2n - 60 ) / [n-3] \n" ); document.write( "quotient= n2 +6n + 20 \n" ); document.write( "=> (n-3) , (n2 +6n + 20) \n" ); document.write( " n3 + 3n2 +2n - 60 = 0 \n" ); document.write( " => (n-3) * (n2 +6n + 20) = 0 \n" ); document.write( "=> (n-3) = 0 or (n2 +6n + 20) = 0 \n" ); document.write( "So n = 3 \n" ); document.write( " \n" ); document.write( " |