document.write( "Question 741213: Respected Sir,
\n" ); document.write( "Please help me to solve this question:\r
\n" ); document.write( "\n" ); document.write( "If(n+2)!=60[(n-1)!],find n.
\n" ); document.write( "Thank you in anticipation.
\n" ); document.write( "

Algebra.Com's Answer #451901 by mananth(16946)\"\" \"About 
You can put this solution on YOUR website!
If (n+2)! = 60[(n-1)!], n=?
\n" ); document.write( "(n+2)! = 60* ( (n-1)! )
\n" ); document.write( "(n+2)! = (n+2) * (n+1) * (n) * (n-1)!
\n" ); document.write( "{ (n+2) * (n+1) * (n) * (n-1)! } = 60* ( (n-1)! )
\n" ); document.write( "=> { (n+2) * (n+1) * (n) * (n-1)! } = 60*( (n-1)! )\r
\n" ); document.write( "\n" ); document.write( "=> n3 + 3n2 +2n - 60 = 0
\n" ); document.write( "for n=3 we get 0 Substitute n = 3
\n" ); document.write( "=>( n3 + 3n2 +2n - 60 ) / [n-3]
\n" ); document.write( "quotient= n2 +6n + 20
\n" ); document.write( "=> (n-3) , (n2 +6n + 20)
\n" ); document.write( " n3 + 3n2 +2n - 60 = 0
\n" ); document.write( " => (n-3) * (n2 +6n + 20) = 0
\n" ); document.write( "=> (n-3) = 0 or (n2 +6n + 20) = 0
\n" ); document.write( "So n = 3
\n" ); document.write( "
\n" ); document.write( "
\n" );