document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=741217>Question 741217</A>: <I><SPAN STYLE=\"word-break: break-all;\"> in a cricket match bye runs were double of the no-balls,the remaining score was greater by six than twelve times the number of bye-runs.if the total score was 276.how were the runs obtained?<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #451897 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=451897\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> No balls----------x\r<BR>\n" );
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document.write( "byes = 2x<BR>\n" );
document.write( "total runs = 276\r<BR>\n" );
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document.write( "remaining runs = (276-3x)=12*2x+6\r<BR>\n" );
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document.write( "276-3x=24x+6\r<BR>\n" );
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document.write( "27x=270\r<BR>\n" );
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document.write( "x=10\r<BR>\n" );
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document.write( "No ball<BR>\n" );
document.write( "s = 10<BR>\n" );
document.write( "Byes = 20<BR>\n" );
document.write( "Runs = 246  </SPAN>\n" );
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