document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=739791>Question 739791</A>: <I><SPAN STYLE=\"word-break: break-all;\"> 6. Given log(3) = 0.47712 , find a approximation for each logarithm<BR>\n" );
document.write( "a) log(30)<BR>\n" );
document.write( "b) log(3000)<BR>\n" );
document.write( "c) log(.3)<BR>\n" );
document.write( "d) log(.003)<BR>\n" );
document.write( "e) log(9)<BR>\n" );
document.write( "f) log(81)<BR>\n" );
document.write( "g) log(&#8730;3)\r<BR>\n" );
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document.write( "Can you please help me out? Thanks so much in advance:) </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #451891 by </B><A HREF=/tutors/aboutme.mpl?userid=lwsshak3><B>lwsshak3(11628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=lwsshak3><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=451891\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 6. Given log(3) = 0.47712 , find a approximation for each logarithm<BR>\n" );
document.write( "a) log(30)=log(10*3)=log(10)+log(3)=1+.47712=1.47712<BR>\n" );
document.write( "b) log(3000)=log(1000*3)=log(1000)+log(3)=3+.47712=3.47712<BR>\n" );
document.write( "c) log(.3)=log(10^(-1)*3)=-1+log(3)=-1+.47712=-0.52288<BR>\n" );
document.write( "d) log(.003)=log(10^(-3)*3)=-3+log(3)=-3+.47712=-2.52288<BR>\n" );
document.write( "e) log(9)=log(3^2)=2log(3)=2*.47712=0.95424<BR>\n" );
document.write( "f) log(81)=log(3^3)=3log(3)=3*.47712=1.43136<BR>\n" );
document.write( "g) log(&#8730;3)=(1/2)log(3)=1/2*.47712=0.23856<BR>\n" );
document.write( "note: log of base raised to an exponent=exponent; e.g. log 10^3=3  </SPAN>\n" );
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