document.write( "Question 741178: a 50-gallon barrel of milk is 6 % butterfat. how much skim milk( no butter fat) should be mixed tot make milk that is 3% butterfat? \n" ); document.write( "

Algebra.Com's Answer #451885 by josgarithmetic(39617) $\"\"$ $\"About$

You can put this solution on YOUR website!
50 gallons, just by one quick read.\r
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\n" ); document.write( "\n" ); document.write( "But if you want some algebraic work, then, this is a dilution exercise.
\n" ); document.write( "Let g = gallons of skim milk to add.
\n" ); document.write( "Note, percent of fat in the skim milk is 0%.
\n" ); document.write( " $\"%2850%2A6%2Bg%2A0%29%2F%2850%2Bg%29=3\"$
\n" ); document.write( "Simplifies to:
\n" ); document.write( " $\"%2850%2A6%29%2F%2850%2Bg%29=3\"$
\n" ); document.write( "Solve for g.\r
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\n" ); document.write( "\n" ); document.write( "Was I correct?
\n" ); document.write( " $\"50%2A6=3%2850%2Bg%29\"$
\n" ); document.write( " $\"50%2A6=3%2A50%2B3g\"$
\n" ); document.write( " $\"3g=50%2A6-3%2A50=50%286-3%29\"$
\n" ); document.write( " $\"3g=50%2A3\"$
\n" ); document.write( " $\"g=50\"$ \r
\n" ); document.write( "\n" ); document.write( "Notice from first-read, the dilution simply cuts the fat concentration exactly in half. \n" ); document.write( "

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