document.write( "Question 64588: on my worksheet it says find the center and the radius of the circle with the given points the problem is x2+y2-6x-2y+5=0 i have to subtract the 5 then what? \n" ); document.write( "

Algebra.Com's Answer #45187 by Earlsdon(6294) $\"\"$ $\"About$

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Find the center and radius of the circle whose equation is:
\n" ); document.write( " $\"x%5E2%2By%5E2-6x-2y%2B5+=+0\"$ Yes, you first subtract 5 from both sides.
\n" ); document.write( " $\"x%5E2%2By%5E2-6x-2y+=+-5\"$ Now group the x-terms together and the y-terms together.
\n" ); document.write( " $\"%28x%5E2-6x%29+%2B+%28y%5E2-2y%29+=+-5\"$ Next, complete the squares in the x-terms and in the y-terms.
\n" ); document.write( " $\"%28x%5E2-6x%2B9%29+%2B+%28y%5E2-2y%2B1%29+=+-5%2B10\"$ Now factor the left side.
\n" ); document.write( " $\"%28x-3%29%5E2+%2B+%28y-1%29%5E2+=+5\"$ Compare this with standard form for a circle with centre at (h, k) and radius r.
\n" ); document.write( " $\"%28x-h%29%5E2+%2B+%28y-k%29%5E2+=+r%5E2\"$
\n" ); document.write( "From this comparison, you can see that the centre of your circle is at (3, 1) and the radius $\"r+=+sqrt%285%29\"$ \n" ); document.write( "

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