document.write( "Question 741077: i need your help i'm stuck.\r
\n" ); document.write( "\n" ); document.write( "i have to find the exact solutions when possible for 0 deg<= x <360 deg or approximate the solution\r
\n" ); document.write( "\n" ); document.write( "cotx=12/13
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Algebra.Com's Answer #451841 by KMST(5328)\"\" \"About 
You can put this solution on YOUR website!
A calculator can give you an approximate solution.
\n" ); document.write( "If \"cot%28x%29=12%2F13\", then \"tan%28x%29=1%2Fcot%28x%29=13%2F12\"
\n" ); document.write( "and the calculator says that \"tan%5E%28-1%29%2813%2F12%29=47.29%5Eo\" so \"tan%2847.29%5Eo%29=13%2F12\"
\n" ); document.write( "\"tan%28x%29\" is positive and increasing in the first and third quadrant, and has a period of \"180%5Eo\"
\n" ); document.write( "The graph below shows \"y=tan%28x%29\" and \"y=13%2F12\"
\n" ); document.write( "\"graph%28300%2C300%2C-45%2C405%2C-5%2C5%2Ctan%28pi%2Ax%2F180%29%2C13%2F12%29\"
\n" ); document.write( "So that \"tan%2847.29%5Eo%29=tan%2847.29%5Eo%2B180%5Eo%29=tan%28227.29%5Eo%29\"
\n" ); document.write( "The only two approximate solutions to \"cot%28x%29=12%2F13\" for \"0%3C=x%3C360%5Eo\" are
\n" ); document.write( "\"highlight%28x=47.29%5Eo%29\" and \"highlight%28x=227.29%5Eo%29\"
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