document.write( "Question 64567: I know the answer is no solution but i need to know how to work this problem please help\r
\n" ); document.write( "\n" ); document.write( "6+log(2,(2x-4))=7+log(2,(3x))
\n" ); document.write( "

Algebra.Com's Answer #45180 by stanbon(75887)\"\" \"About 
You can put this solution on YOUR website!
6+log(2,(2x-4))=7+log(2,(3x))
\n" ); document.write( "Keep in mind, the logs are base two.
\n" ); document.write( "---------
\n" ); document.write( "log(2x-4)=1+log(3x)
\n" ); document.write( "log(2x-4)-log(3x)=1
\n" ); document.write( "log[(2x-4)/3x]=1
\n" ); document.write( "Since the logs are base 2 you get:
\n" ); document.write( "(2x-4)/3x=2^1
\n" ); document.write( "2x-4=6x
\n" ); document.write( "4x=-4
\n" ); document.write( "x=-1
\n" ); document.write( "Checking this in the original equation you get log(-3) which doesn't exist.
\n" ); document.write( "So, no solution.
\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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