document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=740832>Question 740832</A>: <I><SPAN STYLE=\"word-break: break-all;\"> \r<BR>\n" );
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document.write( "A rectangular yard has an area of 2160 square feet.  The length of the yard is three feet longer than its width.  What is the perimeter of the yard? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #451724 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley79><B>checkley79(3341)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley79><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=451724\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> AREA=L*W<BR>\n" );
document.write( "L=W+3<BR>\n" );
document.write( "2,160=(W+3)W<BR>\n" );
document.write( "2,160=W^2+3W<BR>\n" );
document.write( "W^2+3W-2,160=0<BR>\n" );
document.write( "(W+48)(W-45)=0<BR>\n" );
document.write( "W-45=0<BR>\n" );
document.write( "W=45 ANS. FOR THWE WIDTH.<BR>\n" );
document.write( "L=45+3=48 ANS. FOR THE LENGTH.<BR>\n" );
document.write( "PROOF:<BR>\n" );
document.write( "2,160=45*48<BR>\n" );
document.write( "2,160=2,160<BR>\n" );
document.write( "P=2L+2W<BR>\n" );
document.write( "P=2*48+2*45<BR>\n" );
document.write( "P=96+90<BR>\n" );
document.write( "P=186 ANS. FOR THE PERIMETER. </SPAN>\n" );
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