document.write( "Question 740746: Ravi's Coffee Shop makes a blend that is a mixture of two types of coffee. Type A coffee costs $5.45 Ravi per pound, and type B coffee costs $4.20 per pound. This month, Ravi made 121 pounds of the blend, for a total cost of $571.95 . How many pounds of type B coffee did he use? \n" ); document.write( "
Algebra.Com's Answer #451686 by mananth(16946)\"\" \"About 
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x= pounds of coffee type I
\n" ); document.write( "y= pounds of coffee type II
\n" ); document.write( "
\n" ); document.write( "1.00 x + 1.00 y = 121.00 .............1
\n" ); document.write( "Total value
\n" ); document.write( "5.45 x + 4.20 y = 571.95 .............2
\n" ); document.write( "Eliminate y
\n" ); document.write( "multiply (1)by -4.20
\n" ); document.write( "Multiply (2) by 1.00
\n" ); document.write( "-4.20 x -4.20 y = -508.20
\n" ); document.write( "5.45 x + 4.20 y = 571.95
\n" ); document.write( "Add the two equations
\n" ); document.write( "1.25 x = 63.75
\n" ); document.write( "/ 1.25
\n" ); document.write( "x = 51.00
\n" ); document.write( "plug value of x in (1)
\n" ); document.write( "1.00 x + 1.00 y = 121.00
\n" ); document.write( "51.00 + y = 121.00
\n" ); document.write( " y = 121.00 -51.00
\n" ); document.write( " y = 70.00
\n" ); document.write( " y = 70.00
\n" ); document.write( "x= 51.00 pounds of coffee type I
\n" ); document.write( "y= 70.00 pounds of coffee type II
\n" ); document.write( " \n" ); document.write( "
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