document.write( "Question 740753: How many ways can 3 out of 10 students be chosen? \n" ); document.write( "
Algebra.Com's Answer #451682 by jam123(18)![]() ![]() ![]() You can put this solution on YOUR website! Say our students' names are A, B, C..., J. \n" ); document.write( "_ _ _ \n" ); document.write( "1 2 3\r \n" ); document.write( "\n" ); document.write( "Student 1 can be any of the 10 students, so we'll put a 10 there.\r \n" ); document.write( "\n" ); document.write( "10 \n" ); document.write( "-- -- -- \n" ); document.write( " 1 2 3\r \n" ); document.write( "\n" ); document.write( "Student 2 CANNOT be any of the 10 students, as there has already been another student chosen. Thus, the number of students is 9.\r \n" ); document.write( "\n" ); document.write( "10 9 \n" ); document.write( "-- -- -- \n" ); document.write( " 1 2 3\r \n" ); document.write( "\n" ); document.write( "Now that 2 students have been chosen, 8 students can be Student 3.\r \n" ); document.write( "\n" ); document.write( "10 9 8 \n" ); document.write( "-- -- -- \n" ); document.write( " 1 2 3\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "720 \n" ); document.write( "Therefore, there are 720 ways for 3 out of 10 students to be chosen. \n" ); document.write( " |