document.write( "Question 740769: Find the vertex, x- intercepts, and y- intercept of f(x)=x^2-6x+4? \n" ); document.write( "
Algebra.Com's Answer #451678 by Menjax(62)\"\" \"About 
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The y intercept is easy just let x=0
\n" ); document.write( "=0^2-6x0+4
\n" ); document.write( "=4
\n" ); document.write( "Y intercept is 4.\r
\n" ); document.write( "\n" ); document.write( "For the vertex you use a method called \"completing the square\"
\n" ); document.write( "First step is to take out the coefficient of x^2 which is 0 in this case. so we can skip this step.\r
\n" ); document.write( "\n" ); document.write( "Next take the coefficient of x and divide it by 2. Then 'inject' that into the x^2.
\n" ); document.write( "So instead of (x)^2 it's (x-6/2)^2 which is (x-3)^2 simplified. \r
\n" ); document.write( "\n" ); document.write( "Now add the y intercept so it's y=(x-3)^2 + 4.
\n" ); document.write( "If you expand (x-3)^2 it's x^2-6x+9 and that 9 was never there in the beginning equation so to rebalance the equation you need to remove 9 so,
\n" ); document.write( "y=(x-3)^2 + 4 - 9. Which becomes y=(x-3)^2 -5.
\n" ); document.write( "Now let (x-3)^2 = 0
\n" ); document.write( "so solving for x x=3
\n" ); document.write( "Now solcing for y, y = -5
\n" ); document.write( "so the vertex = (3,-5)\r
\n" ); document.write( "\n" ); document.write( "Now let y = 0 to find x intercept
\n" ); document.write( "so 0=(x-3)^2 -5
\n" ); document.write( "so 5=(x-3)^2
\n" ); document.write( "\"x=3%2B-sqrt%285%29\"
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